x^2+6x=118

Solution for x^2+6x=118 equation:

x^2+6x=118

We move all terms to the left:

x^2+6x-(118)=0

a = 1; b = 6; c = -118;
Δ = b2-4ac
Δ = 62-4·1·(-118)
Δ = 508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{508}=\sqrt{4*127}=\sqrt{4}*\sqrt{127}=2\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{127}}{2*1}=\frac{-6-2\sqrt{127}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{127}}{2*1}=\frac{-6+2\sqrt{127}}{2}
$